X^2+2x-41=2x+18

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Solution for X^2+2x-41=2x+18 equation:


Simplifying
X2 + 2x + -41 = 2x + 18

Reorder the terms:
-41 + X2 + 2x = 2x + 18

Reorder the terms:
-41 + X2 + 2x = 18 + 2x

Add '-2x' to each side of the equation.
-41 + X2 + 2x + -2x = 18 + 2x + -2x

Combine like terms: 2x + -2x = 0
-41 + X2 + 0 = 18 + 2x + -2x
-41 + X2 = 18 + 2x + -2x

Combine like terms: 2x + -2x = 0
-41 + X2 = 18 + 0
-41 + X2 = 18

Solving
-41 + X2 = 18

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '41' to each side of the equation.
-41 + 41 + X2 = 18 + 41

Combine like terms: -41 + 41 = 0
0 + X2 = 18 + 41
X2 = 18 + 41

Combine like terms: 18 + 41 = 59
X2 = 59

Simplifying
X2 = 59

Take the square root of each side:
X = {-7.681145748, 7.681145748}

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